∫abf(x)dx=t=a+b−x∫abf(t)dt
∫0af(x)dx=xb=ta∫0bf(abt)⋅abdt
∫aa+Tf(x)dx=x=t+a∫0Tf(t+a)dt
∫abf(x)dx=∗∫cdf(t−cd−c(b−a)+a)⋅b−ad−cdt其中其中t=x−ab−a(d−c)+cx=t−cd−c(b−a)+a
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v1.5.2